7[3-(4+2x)]-2x=-9+2(1-8x)

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Solution for 7[3-(4+2x)]-2x=-9+2(1-8x) equation:


Simplifying
7[3 + -1(4 + 2x)] + -2x = -9 + 2(1 + -8x)
7[3 + (4 * -1 + 2x * -1)] + -2x = -9 + 2(1 + -8x)
7[3 + (-4 + -2x)] + -2x = -9 + 2(1 + -8x)

Combine like terms: 3 + -4 = -1
7[-1 + -2x] + -2x = -9 + 2(1 + -8x)
[-1 * 7 + -2x * 7] + -2x = -9 + 2(1 + -8x)
[-7 + -14x] + -2x = -9 + 2(1 + -8x)

Combine like terms: -14x + -2x = -16x
-7 + -16x = -9 + 2(1 + -8x)
-7 + -16x = -9 + (1 * 2 + -8x * 2)
-7 + -16x = -9 + (2 + -16x)

Combine like terms: -9 + 2 = -7
-7 + -16x = -7 + -16x

Add '7' to each side of the equation.
-7 + 7 + -16x = -7 + 7 + -16x

Combine like terms: -7 + 7 = 0
0 + -16x = -7 + 7 + -16x
-16x = -7 + 7 + -16x

Combine like terms: -7 + 7 = 0
-16x = 0 + -16x
-16x = -16x

Add '16x' to each side of the equation.
-16x + 16x = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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